2008年9月30日星期二

ZJU/ZOJ 1800 Decorations 解题报告

题目大意是求用给定的m个组合组成长度为l的字符串的方案数。

先进行预处理，标记可以作为某些组合的前缀的某些组合的后缀。用f[i,j]表示第i个位置为第j种组合的方案数，则f[i,j]=∑f[i-1,k](pre[j]=last[k]);pre[j]表示第j种组合的前缀，last[k]表示第k种组合的后缀。则所求方案数为∑f[l,j]。

1652446    2008-09-30 22:40:08     Accepted    1800    FPC    660    716    IwfWcf@LZOI

发帖者 IwfWcf 时间： 22:57:00
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