题目大意是有分值为1-6的牌各4张，两人轮流取牌，如果其中一方取牌后对方无论如何取牌都会导致取过的牌的分值总和大于31，则当前取完牌的一方获胜。现给出两人已经取了的一些牌的信息，假设此后两人均使用最优策略取牌，问在当前局面下谁将获胜？
比较经典的博弈类递推模型，如果用f[i1,i2,i3,i4,i5,i6,sum]来表示当前已经取了的6种分值的牌的信息以及取了的牌的分值总和，则显然当sum=31时该状态是必胜态。于是根据博弈类递推问题的递推通式可以确定可以通过单步转化为必胜态的状态必为必败态，类似的，如果一个状态通过单步转化而成的全部是必败态，则其必为必胜态。
3067327 2008-09-12 13:05:46 Accepted 1827 FPC 00:00.01 880K IwfWcf@LZOI
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如果其中一方取牌后对方无论如何取牌都会导致取过的牌的分值总和大于31，则当前取完牌的一方获胜。（病句）
回复删除什么意思？？？？？
我不认为有什么语病，就是按字面意思来理解
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